5.3.5 - Protective conductor impedance
It has been shown in the previous sub-section
how a low-impedance protective conductor will provide safety
from shock in the event of a fault to earth. This method
can only be used where it is certain that the shock victim
can never be in contact with conducting material at a different
potential from that of the earthed system in the zone he
occupies. Thus, all associated exposed or extraneous parts
must be within the equipotential zone (see
{5.4}). When overcurrent protective devices are used
as protection from electric shock, the protective conductor
must be in the same wiring system as, or in close proximity
to, the live conductors. This is intended to ensure that
the protective conductor is unlikely to he damaged in an
accident without the live conductors also being cut.
{Figure 5.9} shows a method of measuring
the resistance of the protective conductor, using a line
conductor as a return and taking into account the different
cross-sectional areas of the phase and the protective conductors.
Fig 5.9 - Measurement
of protective conductor resistance
Taking the cross-sectional area of the
protective conductor as Ap and that of the line
(phase or neutral) conductor as Al , then
Rp = resistance reading
x |
Al |
|
Al + Ap |
For example, consider a reading of 0.72
Ohms obtained when measuring a circuit in the way described
and having 2.5 mm² line conductors and a 1.5 mm² protective
conductor. The resistance of the protective conductor is
calculated from:
Rp = R x
|
Al
|
= 0.72 x 2.5
|
Ohms |
|
Al + Ap
|
2.5 + 1.5
|
|
|
|
|
|
=
|
0.72 x 2.5
|
Ohms = |
0.45 Ohms |
|
4.0
|
|
|
|